(5x+7)(2x^2-5x+3)=0

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Solution for (5x+7)(2x^2-5x+3)=0 equation:


Simplifying
(5x + 7)(2x2 + -5x + 3) = 0

Reorder the terms:
(7 + 5x)(2x2 + -5x + 3) = 0

Reorder the terms:
(7 + 5x)(3 + -5x + 2x2) = 0

Multiply (7 + 5x) * (3 + -5x + 2x2)
(7(3 + -5x + 2x2) + 5x * (3 + -5x + 2x2)) = 0
((3 * 7 + -5x * 7 + 2x2 * 7) + 5x * (3 + -5x + 2x2)) = 0
((21 + -35x + 14x2) + 5x * (3 + -5x + 2x2)) = 0
(21 + -35x + 14x2 + (3 * 5x + -5x * 5x + 2x2 * 5x)) = 0
(21 + -35x + 14x2 + (15x + -25x2 + 10x3)) = 0

Reorder the terms:
(21 + -35x + 15x + 14x2 + -25x2 + 10x3) = 0

Combine like terms: -35x + 15x = -20x
(21 + -20x + 14x2 + -25x2 + 10x3) = 0

Combine like terms: 14x2 + -25x2 = -11x2
(21 + -20x + -11x2 + 10x3) = 0

Solving
21 + -20x + -11x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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